Wednesday, December 14, 2011

The Determination of the Mass of a Product of a Chemical Reaction

(Partner: Nina T.)


Observations:

 Day 1: NaCHO(Baking Soda) + HCl
                                                 
                                         Before: - very white powder with some clumps
                                           
                                         During: - the NaCHObubbled quickly, then popped with smoke
                                                       - less and less NaCHO3, no chunks       
                                                       - solution becomes milk-like in color
                                                       - NaCHOnot dissolved in HCl     
                                                       - with each drop of HCl, more and more bubbles appear 
                                                       - solution becomes clearer and less NaCHO3 is visible






Day 2: NaCHO(Baking Soda) + HCl --> NaCl + CO2 + H2O
                                                 
                                         Before: NaCl formed up along sides of beaker
                                                       - yellow at top edges
                                                       - large NaCl bubbles at bottom of beaker
               

                                           
                           
                                            
                                         
                                         During: - the NaCl begins to make a slight pop noise
                                                       - yellow edges at top become light tan



Day 1 Data
Day 2 Data
Mass
Grams
Mass
Grams
Empty 150ml beaker
73.39g
NaCl plus beaker (first weighing)
78.89g
NaHCO3 in beaker

81.19g
NaCl plus beaker (second weighing)
78.85g



NaCl plus beaker (third weighing)
78.79g


Discussion Questions:


1) Write the grams of NaHCO3 you had in your beaker.
          81.19g - 73.39g = 7.8g NaHCO3


2) Calculate how many moles of NaHCO3 the mass is.
                                                                                     
    7.8g
NaHCO3
 1 mole

 84.02g
NaHCO3                  

= 0.09 mol NaHCO3 

3) Write the molar ratio for the NaHCO3 / NaCl ratio. 
         1 NaHCO3 : 1 NaCl

4) Write the number of moles of NaCl you predict were produced in your experiment. 

 7.8g
NaHCO3
 1 mol
 1 NaCl

 84.02g
NaHCO3
 1
NaHCO3

= 0.09 mol NaCl 


5) Calculate the mass of NaCl you predict will be produced.

 7.8g
NaHCO3
 1 mol
 1 NaCl
 58.45g NaCl

 84.02g
NaHCO3
 1
NaHCO3
 1 mol
= 5.43g NaCl

6) Determine, by subtraction, the actual mass of NaCl produced in your experiment. 

   a) First weighing:  78.98g NaCl - 73.39g (mass of beaker) = 5.59g NaCl
   b) Second weighing:  78.85g NaCl - 73.39g = 5.46g NaCl
   c) Third weighing:  78.79g NaCl - 73.39g = 5.40g NaCl

7) Calculate your percentage yield. 

    5.4g NaCl
    5.43g NaCl

x100 = 99% yield

8) What are plausible reasons why your percent yield is less than 100%?
         -We did not use enough NaHCO3.
9) What are plausible reasons why your percent yield is more than 100%?
         -We used too much NaHCO3.                                                   

No comments:

Post a Comment