Observations:
Day 1: NaCHO3 (Baking Soda) + HCl
Before: - very white powder with some clumps
During: - the NaCHO3 bubbled quickly, then popped with smoke
- less and less NaCHO3, no chunks
- solution becomes milk-like in color
- NaCHO3 not dissolved in HCl
- with each drop of HCl, more and more bubbles appear
- solution becomes clearer and less NaCHO3 is visible
Day 2: NaCHO3 (Baking Soda) + HCl --> NaCl + CO2 + H2O
Before: - NaCl formed up along sides of beaker
- yellow at top edges
- large NaCl bubbles at bottom of beaker
During: - the NaCl begins to make a slight pop noise
- yellow edges at top become light tan
Day 1 Data | Day 2 Data | ||
Mass | Grams | Mass | Grams |
Empty 150ml beaker | 73.39g | NaCl plus beaker (first weighing) | 78.89g |
NaHCO3 in beaker | 81.19g | NaCl plus beaker (second weighing) | 78.85g |
NaCl plus beaker (third weighing) | 78.79g |
Discussion Questions:
1) Write the grams of NaHCO3 you had in your beaker.
81.19g - 73.39g = 7.8g NaHCO3
2) Calculate how many moles of NaHCO3 the mass is.
7.8g NaHCO3 | 1 mole |
84.02g NaHCO3 |
= 0.09 mol NaHCO3
3) Write the molar ratio for the NaHCO3 / NaCl ratio.
1 NaHCO3 : 1 NaCl
4) Write the number of moles of NaCl you predict were produced in your experiment.
7.8g NaHCO3 | 1 mol | 1 NaCl |
84.02g NaHCO3 | 1 NaHCO3 |
= 0.09 mol NaCl
5) Calculate the mass of NaCl you predict will be produced.
5) Calculate the mass of NaCl you predict will be produced.
7.8g NaHCO3 | 1 mol | 1 NaCl | 58.45g NaCl |
84.02g NaHCO3 | 1 NaHCO3 | 1 mol |
= 5.43g NaCl
6) Determine, by subtraction, the actual mass of NaCl produced in your experiment.
a) First weighing: 78.98g NaCl - 73.39g (mass of beaker) = 5.59g NaCl
b) Second weighing: 78.85g NaCl - 73.39g = 5.46g NaCl
c) Third weighing: 78.79g NaCl - 73.39g = 5.40g NaCl
7) Calculate your percentage yield.
5.4g NaCl |
5.43g NaCl x100 = 99% yield |
8) What are plausible reasons why your percent yield is less than 100%?
-We did not use enough NaHCO3.
9) What are plausible reasons why your percent yield is more than 100%?
-We used too much NaHCO3.
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